Surds
Lesson Objectives
By the end of this lesson, students should be able to:
- Define surds and distinguish them from rational and irrational numbers.
- Simplify simple and compound surds.
- Add, subtract, multiply, and divide surds.
- Rationalize the denominator involving surds.
Introduction
A surd is an irrational number that cannot be simplified to remove the root symbol entirely. For example, \(\sqrt{2}\) is a surd, but \(\sqrt{4} = 2\) is not.
Core Lesson Content
Key laws of surds:
- \(\sqrt{a} \times \sqrt{b} = \sqrt{ab}\)
- \(\frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}\)
- \((\sqrt{a})^2 = a\)
Simplification of Surds
\(\sqrt{72} = \sqrt{36 \times 2} = \sqrt{36} \times \sqrt{2} = 6\sqrt{2}\)
Answer: \(6\sqrt{2}\)
\((2 + 5)\sqrt{3} = 7\sqrt{3}\)
Answer: \(7\sqrt{3}\)
Multiplication and Division
\(= \sqrt{36} = 6\)
Answer: 6
\(= \sqrt{9} = 3\)
Answer: 3
Rationalization
\(= \frac{5\sqrt{2}}{2}\)
Answer: \(\frac{5\sqrt{2}}{2}\)
Multiply by conjugate: \(\frac{3(1 + \sqrt{2})}{(1 - \sqrt{2})(1 + \sqrt{2})} = \frac{3(1 + \sqrt{2})}{-1} = -3 - 3\sqrt{2}\)
Answer: \(-3 - 3\sqrt{2}\)
Compound Surds
\(= 2\sqrt{3} + 3\sqrt{3} = 5\sqrt{3}\)
Answer: \(5\sqrt{3}\)
\(= 2\sqrt{5} - \sqrt{5} = \sqrt{5}\)
Answer: \(\sqrt{5}\)
Using Surds in Algebra
\(b = \sqrt{8} = 2\sqrt{2}\), so \(a + b = \sqrt{2} + 2\sqrt{2} = 3\sqrt{2}\)
Answer: \(3\sqrt{2}\)
\(= (\sqrt{2})^2 + 2 \cdot \sqrt{2} \cdot 1 + 1^2 = 2 + 2\sqrt{2} + 1 = 3 + 2\sqrt{2}\)
Answer: \(3 + 2\sqrt{2}\)
Exercises
- Simplify \(\sqrt{72}\)
- Simplify \(2\sqrt{3} + 5\sqrt{3}\)
- Multiply \(\sqrt{2} \times \sqrt{18}\)
- Rationalize \(\frac{5}{\sqrt{2}}\)
- Evaluate \(\sqrt{12} + \sqrt{27}\)
- [WAEC] Simplify \(\sqrt{75} - \sqrt{12}\) (Past Question)
- Simplify \(\frac{\sqrt{3}}{\sqrt{5}}\)
- [NECO] Rationalize and simplify \(\frac{2}{1 + \sqrt{3}}\) (Past Question)
- [JAMB] If \(a = \sqrt{2}, b = \sqrt{8}\), simplify \(a + b\) (Past Question)
- Expand \((\sqrt{2} + 1)^2\)
Conclusion / Recap
Surds are roots that cannot be expressed as exact rational numbers. In this lesson, we have explored simplification, rationalization, and operations on surds. Mastery of surds is crucial for progressing to logarithms and advanced algebra.
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