Surds
Lesson Objectives
By the end of this lesson, students should be able to:
- Define surds and distinguish them from rational and irrational numbers.
- Simplify simple and compound surds.
- Add, subtract, multiply, and divide surds.
- Rationalize the denominator involving surds.
Introduction
A surd is an irrational number that cannot be simplified to remove the root symbol entirely. For example, \sqrt{2} is a surd, but \sqrt{4} = 2 is not.
Core Lesson Content
Key laws of surds:
- \sqrt{a} \times \sqrt{b} = \sqrt{ab}
- \frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}
- (\sqrt{a})^2 = a
Simplification of Surds
Example 1: Simplify \sqrt{72}.
\sqrt{72} = \sqrt{36 \times 2} = \sqrt{36} \times \sqrt{2} = 6\sqrt{2}
\sqrt{72} = \sqrt{36 \times 2} = \sqrt{36} \times \sqrt{2} = 6\sqrt{2}
Answer: 6\sqrt{2}
Example 2: Simplify 2\sqrt{3} + 5\sqrt{3}.
(2 + 5)\sqrt{3} = 7\sqrt{3}
(2 + 5)\sqrt{3} = 7\sqrt{3}
Answer: 7\sqrt{3}
Multiplication and Division
Example 3: Multiply \sqrt{2} \times \sqrt{18}.
= \sqrt{36} = 6
= \sqrt{36} = 6
Answer: 6
Example 4: Divide \frac{\sqrt{27}}{\sqrt{3}}.
= \sqrt{9} = 3
= \sqrt{9} = 3
Answer: 3
Rationalization
Example 5: Rationalize \frac{5}{\sqrt{2}}.
= \frac{5\sqrt{2}}{2}
= \frac{5\sqrt{2}}{2}
Answer: \frac{5\sqrt{2}}{2}
Example 6: Rationalize \frac{3}{1 - \sqrt{2}}.
Multiply by conjugate: \frac{3(1 + \sqrt{2})}{(1 - \sqrt{2})(1 + \sqrt{2})} = \frac{3(1 + \sqrt{2})}{-1} = -3 - 3\sqrt{2}
Multiply by conjugate: \frac{3(1 + \sqrt{2})}{(1 - \sqrt{2})(1 + \sqrt{2})} = \frac{3(1 + \sqrt{2})}{-1} = -3 - 3\sqrt{2}
Answer: -3 - 3\sqrt{2}
Compound Surds
Example 7: Simplify \sqrt{12} + \sqrt{27}.
= 2\sqrt{3} + 3\sqrt{3} = 5\sqrt{3}
= 2\sqrt{3} + 3\sqrt{3} = 5\sqrt{3}
Answer: 5\sqrt{3}
Example 8: Simplify \sqrt{20} - \sqrt{5}.
= 2\sqrt{5} - \sqrt{5} = \sqrt{5}
= 2\sqrt{5} - \sqrt{5} = \sqrt{5}
Answer: \sqrt{5}
Using Surds in Algebra
Example 9: If a = \sqrt{2}, b = \sqrt{8}, find a + b.
b = \sqrt{8} = 2\sqrt{2}, so a + b = \sqrt{2} + 2\sqrt{2} = 3\sqrt{2}
b = \sqrt{8} = 2\sqrt{2}, so a + b = \sqrt{2} + 2\sqrt{2} = 3\sqrt{2}
Answer: 3\sqrt{2}
Example 10: Expand (\sqrt{2} + 1)^2.
= (\sqrt{2})^2 + 2 \cdot \sqrt{2} \cdot 1 + 1^2 = 2 + 2\sqrt{2} + 1 = 3 + 2\sqrt{2}
= (\sqrt{2})^2 + 2 \cdot \sqrt{2} \cdot 1 + 1^2 = 2 + 2\sqrt{2} + 1 = 3 + 2\sqrt{2}
Answer: 3 + 2\sqrt{2}
Exercises
- Simplify \sqrt{72}
- Simplify 2\sqrt{3} + 5\sqrt{3}
- Multiply \sqrt{2} \times \sqrt{18}
- Rationalize \frac{5}{\sqrt{2}}
- Evaluate \sqrt{12} + \sqrt{27}
- [WAEC] Simplify \sqrt{75} - \sqrt{12} (Past Question)
- Simplify \frac{\sqrt{3}}{\sqrt{5}}
- [NECO] Rationalize and simplify \frac{2}{1 + \sqrt{3}} (Past Question)
- [JAMB] If a = \sqrt{2}, b = \sqrt{8}, simplify a + b (Past Question)
- Expand (\sqrt{2} + 1)^2
Conclusion / Recap
Surds are roots that cannot be expressed as exact rational numbers. In this lesson, we have explored simplification, rationalization, and operations on surds. Mastery of surds is crucial for progressing to logarithms and advanced algebra.
Clip It!
Share your ANSWER in the Chat. Indicate TITLE e.g Linear Equation 1. .....2. e.t.c
